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1/2x^2-x-3/2=6()x
We move all terms to the left:
1/2x^2-x-3/2-(6()x)=0
Domain of the equation: 2x^2!=0We add all the numbers together, and all the variables
x^2!=0/2
x^2!=√0
x!=0
x∈R
-1x+1/2x^2-(6()x)-3/2=0
We calculate fractions
-1x-(6()x)=0
We calculate terms in parentheses: -(6()x), so:
6()x
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6()x
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6()x
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6()x
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6()x
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